摘要
根据生化需要量公式y（t）=L1=L0（1-e^-k1t）,且[t/y（t）]^1/3-t是线性关系,由直线的斜率和截距求出耗氧系数k1和水中总的生化需氧量L0。由动力学方程求出任意时间t的y（t）,可知水库的污染程度,从而制定富营养化水体的处理方案,建立水库水污染的控制模型。
Based on the BOD formula y（t）=L1=L0（1-e^-kt）,and [t/y（t）]^1/3-t is liner relation, the k1 and L0 was obtained by out of the slope and the y - intercept, and y（t） at any time was obtained by kinetic equation, from which the level of pollution was known. Then, a plan for treatment of waste water can be worked out, and a pollution control model for the water of drinking water source Tangpu Reservoir was established.
出处
《安徽农业科学》
CAS
北大核心
2009年第6期2684-2685,共2页
Journal of Anhui Agricultural Sciences
基金
浙江生态省建设重大科技攻关项目(2005C13002)
